The 220 V lamps, one of 60 W and the other of 75 W are connected in series across a 440 V supply. The potential difference across 60 W lamp will be

Question

RRB Paper · Accepted Answer

Using the values given:

To find the resistance of each bulb, we can use the formula:

Power = V^2 / R

For the 60 W bulb:

R1 = V^2 / Power = 220^2 / 60 = 806.67 Ω

For the 75 W bulb:

R2 = V^2 / Power = 220^2 / 75 = 645.33 Ω

The total resistance of the circuit is the sum of the resistances of the two bulbs:

R = R1 + R2 = 1452 Ω

The current flowing through the circuit is:

I = V / R = 220 / 1452 = 0.151 A

The potential difference across the 60 W bulb can be found using Ohm's law:

V1 = I * R1 = 0.151 * 806.67 = 242.99 V

So the potential difference across the 60 W bulb is approximately 242 V.

195 V