If a 3-phase induction motor is running at slip s, then rotor copper loss is equal to.

Question

RRB Paper · Accepted Answer

If a 3-phase induction motor is running at slip s, then rotor copper loss is equal to s² × (1-s).

The rotor copper loss is given by the formula: Rotor copper loss = s² × Rotor input power

This is because the rotor copper loss is proportional to the square of the rotor current, which is proportional to the square of the slip. Therefore, the rotor copper loss is proportional to s².

The rotor input power is given by the formula: Rotor input power = (1 - s) × Stator input power

Therefore, the ratio of rotor copper loss to rotor input power is:

Rotor copper loss / Rotor input power = (s² × Rotor input power) / ((1 - s) × Stator input power)

= s² / (1 - s)

If a 3-phase induction motor is running at slip s, then rotor copper loss is equal to.

(1 - s) × Rotor Input

(1 + s) × Rotor input

s × Rotor input

s^2 × (1-s)

The correct answer is `No. 4: s^2 × (1-s)`

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If a 3-phase induction motor is running at slip s, then rotor copper loss is equal to.

(1 - s) × Rotor Input

(1 + s) × Rotor input

s × Rotor input

s^2 × (1-s)

The correct answer is No. 4: s^2 × (1-s)

The correct answer is `No. 4: s^2 × (1-s)`