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Engineering strain of a mild steel sample is recorded as 0.100%. The true strain is ______

True strain (?T) = ln (1 + ?)

Calculation:

Given:

Engineering strain (?) = $(\varepsilon ) = 0.100{\rm{\% }} = \frac{{0.1}}{{100}} = 0.001$

True strain (?T) = ln (1 + ?)

?T = ln (1 + 0.001)

?T = 0.099%