A 3-phase induction motor is running at 2% slip. If the input to rotor is 1000 W, then mechanical power developed by the motor is

Question

RRB Paper · Accepted Answer

The mechanical power developed by a 3-phase induction motor is

Pmech = (1 - s) * Prot

where

Pmech is the mechanical power developed by the motor
s is the slip
rot is the input power to the rotor.

In this case, the slip is 2% or 0.02, and the input power to the rotor is 1000 W.

Substituting these values in the formula, we get:

Pmech = (1 - 0.02) * 1000 W

Pmech = 0.98 * 1000 W

Pmech = 980 W

500 W