The bearing of line AB is 150°15’ and the angle ABC between line AB and BC is 110°30' as shown in the given figure.
What is the bearing of line BC?
![Deflection angle between the line AB and BC at B = 360° ? ?B Bearing of BC = 110°30` – (360° – B.B. of AB) = 110°30` – [360° – (150°15` + 180°)] = 80°45`](https://rrbpaper.com/static/questions_images/1674567570187.ans.11.jpg)
Deflection angle between the line AB and BC at B = 360° − ∠B
Bearing of BC = 110°30` – (360° – B.B. of AB)
= 110°30` – [360° – (150°15` + 180°)]
= 80°45`