The following data pertain to a sewage sample at a point source.

Initial dissolved oxygen (DO) = 12 mg/l; Final DO = 4 mg/l; Dilution of sewage was done to 2%.

The Biochemical oxygen demand (BOD) of the given sample sewage is :

Question

The following data pertain to a sewage sample at a point source.

Initial dissolved oxygen (DO) = 12 mg/l; Final DO = 4 mg/l; Dilution of sewage was done to 2%.

The Biochemical oxygen demand (BOD) of the given sample sewage is :

rrbpapers · Accepted Answer

We know BOD = (Initial DO - Final DO) × Dilution Factor Where Dilution factor = (volume of diluted sample)/(volume of undiluted sewage sample) Initial DO = 12 mg/l Final DO = 2 mg/l 2% diluted sample means: 2 ml of sewage is diluted to make 100 ml of test sample; and hence dilution factor would be 100, as 2 ml has been diluted by 100 times to make 100 ml. Hence volume of diluted sample = 100 ml Volume of undiluted sewage sample = 2 BOD = (12 − 4) × 100/2 = 400 mg/l

The following data pertain to a sewage sample at a point source.

Initial dissolved oxygen (DO) = 12 mg/l; Final DO = 4 mg/l; Dilution of sewage was done to 2%.

The Biochemical oxygen demand (BOD) of the given sample sewage is :

80 mg/l

8 mg/l

800 mg/l

400 mg/l

The correct answer is `No. 4: 400 mg/l`

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The following data pertain to a sewage sample at a point source. Initial dissolved oxygen (DO) = 12 mg/l; Final DO = 4 mg/l; Dilution of sewage was done to 2%. The Biochemical oxygen demand (BOD) of the given sample sewage is :

80 mg/l

8 mg/l

800 mg/l

400 mg/l

The correct answer is No. 4: 400 mg/l

The following data pertain to a sewage sample at a point source.

Initial dissolved oxygen (DO) = 12 mg/l; Final DO = 4 mg/l; Dilution of sewage was done to 2%.

The Biochemical oxygen demand (BOD) of the given sample sewage is :

The correct answer is `No. 4: 400 mg/l`