What is the percentage voltage error of a potential transformer with the system voltage of 11,000 V and having turns ratio of 100, if the measured secondary side voltage is 105 V?
Percentage voltage error = (Nominal voltage - Primary voltage) / Primary voltage x 100%
Nominal voltage is the system voltage
Primary voltage is the actual voltage in the primary circuit
the turns ratio of the potential transformer is given by V1/V2 = N1/N2.
Using the values provided in the question, we have:
V1/V2 = N1/N2 = 100/1 = 100
V1 = 100 x V2 = 100 x 105 V = 10,500 V
Percentage voltage error = (11,000 V - 10,500 V) / 10,500 V x 100%
Percentage voltage error = 500 V / 10,500 V x 100%
Percentage voltage error = 4.76%