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What is the percentage voltage error of a potential transformer with the system voltage of 11,000 V and having turns ratio of 100, if the measured secondary side voltage is 105 V?

Percentage voltage error = (Nominal voltage - Primary voltage) / Primary voltage x 100%

where

Nominal voltage is the system voltage

Primary voltage is the actual voltage in the primary circuit

the turns ratio of the potential transformer is given by V1/V2 = N1/N2.

Using the values provided in the question, we have:

V1/V2 = N1/N2 = 100/1 = 100

V1 = 100 x V2 = 100 x 105 V = 10,500 V

Percentage voltage error = (Nominal voltage - Primary voltage) / Primary voltage x 100%

Percentage voltage error = (11,000 V - 10,500 V) / 10,500 V x 100%

Percentage voltage error = 500 V / 10,500 V x 100%

Percentage voltage error = 4.76%