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For plane (1 1 0) of BCC having a lattice parameter ‘a’, planar atomic density is given by?

The rectangle is made up of four hexagonal molecules joined along their edges to form a rectangle.

The atomic arrangement on the rectangle (1 1 0) in a (BCC) unit cell indicates.

4 corners × 1/2 per corner atom = 2 atom

Area of rectangle = √2 × a × a

= √2a2

Therefore, the number of atoms per square inch which is nothing but its planar density = \(\frac{2}{{1.414{a^2}}} = \frac{{1.414}}{{{a^2}}}\)