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The power supplied to a three-phase induction motor is 32 kW and the stator losses are 1200 Watt. If the slip is 5 percent. determine the rotor copper loss

Input Power of rotor = Stator Input Power - Stator Losses

Stator Input Power = 32 kW

Stator Losses = 1200 W = 1.2 kW

Stator Input Power = Input Power of rotor + Stator Losses

32 kW = Input Power of rotor + 1.2 kW

Input Power of rotor = 32 kW - 1.2 kW = 30.8 kW

Slip = (Rotor copper loss) / (Rotor Input Power)

5/100 = (Rotor copper loss) / (30.8 kW)

(Rotor copper loss) = (5/100) x (30.8 kW) = 1.54 kW

So, the answer is 1.54 kW.