The thermal efficiency of a Carnot heat engine is given by

η = 1 − T₂/T₁

η = 0.3 (given)

0.3 = 1 − T₂/T₁

T₂/T₁ = 0.7

(COP)_HP = T₁/(T₁ − T₂)

1/(1 − 0.7) = 1/0.3

(COP)_HP =3.33

Question

The thermal efficiency of a Carnot heat engine is 30%. If the engine is reversed in operation to work as a heat pump with operating conditions unchanged, then what will be the COP for heat pump?

RRB Paper · Accepted Answer

The thermal efficiency of a Carnot heat engine is given by η = 1 − T2/T1 η = 0.3 (given) 0.3 = 1 − T2/T1 T2/T1 = 0.7 (COP)HP = T1/(T1 − T2) 1/(1 − 0.7) = 1/0.3 (COP)HP =3.33

The thermal efficiency of a Carnot heat engine is 30%. If the engine is reversed in operation to work as a heat pump with operating conditions unchanged, then what will be the COP for heat pump?

3.33

0.30

1.33

2.33

The correct answer is `No. 1: 3.33`

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The thermal efficiency of a Carnot heat engine is 30%. If the engine is reversed in operation to work as a heat pump with operating conditions unchanged, then what will be the COP for heat pump?

3.33

0.30

1.33

2.33

The correct answer is No. 1: 3.33

The correct answer is `No. 1: 3.33`